|
Post by Chilehead on Apr 29, 2008 22:39:47 GMT -5
You're sitting in a boat in a swimming pool. You have a large anchor in the boat. You drop the anchor into the water, and, of course, it sinks immediately. What happens to the water level in the pool?
A. It goes up.
B. It goes down.
C. It stays the same.
Explain why.
|
|
|
Post by ken on Apr 30, 2008 0:23:41 GMT -5
There are no boats in swimming pools!!
|
|
|
Post by Chilehead on Apr 30, 2008 8:59:41 GMT -5
There is in this one.
|
|
|
Post by Osprey on Apr 30, 2008 10:50:23 GMT -5
The water level will stay the same... The reason, I think, is that the weight of the anchor, even though still in the boat, would have displaced the same amount of water as when it was thrown overboard...
|
|
|
Post by Chilehead on Apr 30, 2008 11:35:29 GMT -5
That is incorrect but you are thinking in the right direction.
|
|
|
Post by Osprey on Apr 30, 2008 13:16:33 GMT -5
ok... this was my second choice (i really thought it would stay the same) but after finding where I kept all my phsyics stuff in my brain, I've decided that the water level will go down.
The level will go down because there was more water displaced with the anchor in the boat in order to keep the boat from sinking... when the anchor is tossed overboard, the anchor is now displacing only it's weight. The boat is now displacing less water and will appear to rise a little bit.
|
|
|
Post by Chilehead on Apr 30, 2008 14:46:00 GMT -5
The water level will go down is correct.
While the anchor is in the boat it displaces it's weight. When the anchor is in the water it displaces only it's volume. Since the weight of the anchor is obviously much more than it's volume, it displaces more water while in the boat than in the water. Therefore the water level goes down when the anchor is thrown out of the boat and into the water.
Way to go, Os.
|
|